quote:

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Originally posted by mr_porteiro_head:
That's not unanswerable.

The answer is "Pi".

Another answer is "circumference/diameter".

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Hence the title "Stupid Math Questions".
 

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Posted by Irregardless (Member # 8529) on :
 
Hmmm, I meant to specify positive integers (I was thinking that was what 'whole numbers' were). In any case, the 4 answers I referred to are all greater than 1.
 

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Posted by Irregardless (Member # 8529) on :
 
Maybe I should have said 'cardinal numbers.'
 

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Posted by mr_porteiro_head (Member # 4644) on :
 
You can't change the rules after I've already won.
 

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Posted by kaioshin00 (Member # 3740) on :
 

code:

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 log(10^(ln(e^(log(10^(ln e^42)))))) 

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quote:

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Originally posted by mr_porteiro_head:
You can't change the rules after I've already won.

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Fine, go ahead (although negative one was a wrong answer).
 

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Posted by Geekazoid99 (Member # 8254) on :
 
Acually -1 is a right answer

-1*-1=1
1*-1=-1

HE's right about that one Irregardless
 

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Posted by Irregardless (Member # 8529) on :
 
Uh, no. (-1)^3 is -1, but I said the number is equal to the sum of the cubes of its digits. The digit in -1 is 1. 1^3 = +1.
 

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Posted by Irregardless (Member # 8529) on :
 
BTW, how would you have expressed the answer to the Googolplex number as a fraction?
 

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Posted by mr_porteiro_head (Member # 4644) on :
 
Irr is correct. -1 doesn't fit the rules he stated.

Zero does, though.
 

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Posted by Geekazoid99 (Member # 8254) on :
 
Damn mistakes

What is .99999999999... squared

There's two answers
 

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Posted by mr_porteiro_head (Member # 4644) on :
 
Since 0.9999999999999... is the same thing as 1.0, the answer is 1.0.
 

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Posted by Geekazoid99 (Member # 8254) on :
 
Thats one answer the other is if you take .99999999... to mean .999999... and is not 1
 

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Posted by mr_porteiro_head (Member # 4644) on :
 
I have no idea what you just said.
 

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Posted by Geekazoid99 (Member # 8254) on :
 
I mean if you could write on a calculator .9999999999999999... and squared it what would the result be

If thats too hard here's an easy one

WHats the largest number you can make with 2 digits?
 

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Posted by kaioshin00 (Member # 3740) on :
 
Aw no one answered mine.

What is log(10^(ln(e^(log(10^(ln e^42))))))
 

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Posted by fugu13 (Member # 2859) on :
 
Geekazoid: I don't know about you, but I can keep adding factorial signs on the end of 99 until the cows come home.

Kaioshin: 42, of course
 

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Posted by Geekazoid99 (Member # 8254) on :
 
Oh i could do it alot easier like this

9↑↑↑↑↑↑↑↑↑9 IS probabbly already bigger than your writing with factorials

or even more of those bigger numbers
 

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Posted by HollowEarth (Member # 2586) on :
 
Come on guy's, how many zeros? I assure you there is a simple way to get the right number. Look factorial(3^19) has 290565359 zeros.
 

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Posted by fugu13 (Member # 2859) on :
 
Geekazoid: you can't layer exponents like that, they're binary operators. Factorial, however, is a unary operator.
 

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Posted by mr_porteiro_head (Member # 4644) on :
 

quote:

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I mean if you could write on a calculator .9999999999999999... and squared it what would the result be

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quote:

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What is .99999999999... squared

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quote:

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How many consecutive trailing zeros are there in Factorial(3^12)?

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quote:

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Originally posted by Reticulum:
Say, you wouldn't be the same Oviraptor who finds their way onto all of the Jp boards/ reg boards across the internet are you?

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Nope. I am only a member of one other forum. Only in that forum, I don't have a typo in my user name.

Am I supposed to give a new math problem now?
 

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Posted by Reticulum (Member # 8776) on :
 
Huh. Well, yes, you are. got any good ones?
 

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Posted by Oviratptor (Member # 9323) on :
 
X^3 + Y^3 + Z^3 = 3

One soltution is (1,1,1)

Find 3 more using only integers.
 

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Posted by Irregardless (Member # 8529) on :
 
(-5, 4, 4)
 

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Posted by human_2.0 (Member # 6006) on :
 
Exactly how big of ints?

This:

#!/usr/bin/perl

$start = -100;
$end = 100;

for ( $x = $start; $x lt $end ; $x++ ) {
for ( $y = $start; $y lt $end ; $y++ ) {
for ( $z = $start; $z lt $end ; $z++ ) {
if ( $x*$x*$x + $y*$y*$y + $z*$z*$z == 3 ) {
print "x $x y $y z $z\n";
}
}
}
}

(the forum wouldn't let me include less then, so I have lt instead)

says the answers are:

(-5, 4, 4)
(1, 1, 1)
(4, -5, 4)
(4, 4, -5)

I have a grid running right now... Should I submit this with a humongoidly large range? hahahahaha

I was running -1000 to 1000 but my laptop got so hot it shut itself off.
 

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Posted by Jonathan Howard (Member # 6934) on :
 
How come if I hand out no oranges to no kids, each of them has an orange I handed to them?!
 

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Posted by mr_porteiro_head (Member # 4644) on :
 
For the same reason each one of them has no oranges, and each one has exactly PI oranges.
 

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Posted by Althai (Member # 9275) on :
 

quote:

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Name any whole number (aside from 1) which is equal to the sum of the cubes of its digits.

I.e., XYZ = X^3 + Y^3 + Z^3 (where X, Y & Z are digits, not multiplied terms)

There are only 4 possible answers.

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quote:

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What is the lowers prime number with more than 3 digits which contains only prime numbers as integers. For example 13 contains all prime numbers, but 43 does not

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