posted
Try splitting it into two right triangles of 22, 14, and ~17 (draw a line from the halfway point of the 28 side to the vertex between the 22 sides), and see what you can do from there.
Posts: 293 | Registered: Jun 2004
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posted
Well, once you do what Bekenn said, you can use the law of sines to find the two base angles. Then subtract the two of those from 180 and you have you vertex.
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