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» Hatrack River Forum » Active Forums » Books, Films, Food and Culture » Has anybody ever heard of this? ENTER AT YOUR OWN PERSONAL HEALTH RISK (Page 1)

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Author Topic: Has anybody ever heard of this? ENTER AT YOUR OWN PERSONAL HEALTH RISK
wieczorek
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Here are some guidelines for this project my teacher assigned to us a while ago. It's actually difficult to come up with more than 70% of the 100 numbers you need...

1). you may only use four nines - no more, no less, no other numbers. FOUR NINES.
2). you may use any number of mathematical operations to come up with the numbers 1-100 - pi is not a mathematical operation, it is a way to disguise the number 3.14...

These are the rules from my teacher and ... she SAID we could get help, so if anyone knows of any other mathematical operations than the ones listed below...
( ∙ multiply) ( / divide) ( √ square root) ( − subtract) ( ! factorial) ( 9 multiply by the ninth power) ( + add)

Thanks [Blushing]

[ September 30, 2003, 07:14 PM: Message edited by: wieczorek ]

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Paul Goldner
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you can use the ninth root.
log, log base 9, and ln
sin, cos, tan, cot, sec, cosec,

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wieczorek
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I'll have to ask her if she considers sin, cosine and tangent to be mathematical operations - she's rather...choosy...
Thanks [Smile]

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Paul Goldner
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If she doesn't, hit her [Smile]
They're trigonomentric relationships. so.

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katharina
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quote:
If she doesn't, hit her
Good grief. *wrinkles nose*
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Paul Goldner
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Thats why the smiley is there.

*grumbles*

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wieczorek
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well, that's not a bad idea, paul [Smile] ...but this lady's also the only teacher in my school with a sense of humor! It's rare these days that you ever find a math teacher who can make you laugh.

Teacher: (points to poster on wall) Have a look. Tommy, why don't you read it for us ?

Tommy: 4 out of 3 people find fractions challenging .

Everyone: ...

Everyone ten seconds later: (laughing)

[Razz]

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rivka
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I remember this assignment!

I don't think the trig functions are very helpful -- you get decimals, mostly.

It's been a while, but I seem to recall that it was doable. Some numbers were hard, but all were doable.

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Paul Goldner
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Yeah, factorial isn't very helpful either.
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wieczorek
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I have about 70 right now, but I'm not too worried about it - our teacher said she didn't think anyone would get close to 100...

...which makes me all the more determined! [Big Grin]

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wieczorek
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factorial isn't helpful?
(((√9)!)-9/9)*9

[ September 30, 2003, 03:56 PM: Message edited by: wieczorek ]

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T. Analog Kid
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<wonders if you get to turn the 9's upside down and make sixes of them>

<also wonders if it would help to write out each "9" as a sum, like 3+3+1+1+1, or something like that>

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wieczorek
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good idea, tak [Big Grin] But sadly we can only use four nines (no other numbers! silliness)
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T. Analog Kid
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well, it's still a "9" it's just in different notation, right? [Wink]

sorry... I'm lazy and always look for the easy way out of things...

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Paul Goldner
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I think thats the only one you can get with factorial.

Don't underestimate the power of the trig functions. I believe you can get 2 or 3 with the cofunctions.

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wieczorek
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don't worry about it, tak. Today in class you should have seen me. [Laugh]

The problem of the day was a cake. Yes, a cake. Well, a drawing of one, anyway. We had to find the largest number of pieces that could be made out of using three straight cuts on a cylindrical cake. I happened to miss the part about using only three straight cuts and somehow the problem came across to me as: what is that largest number of pieces you can get out of this cake when cutting with straight lines?

Hmm...funny that I was chosen to show my answer...

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blacwolve
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Um, what exactly is the goal here?
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wieczorek
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Paul - (((9!)+9)-9!)-9!
[((√9)!)!)/9+√9)]-9
(√9!+9/9)*9
[((√9)!)!)/9+√9)]+9
Heehee, I couldn't resist. [Big Grin]

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BannaOj
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which numbers specifically are you having trouble with?
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wieczorek
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blacwolve - hmmm...I think I've lost track myself... [Angst]
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wieczorek
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BannaOj, well...be prepared, it's a whopper! - all of the forties but 45 and all of the fifties but 51
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T. Analog Kid
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what about using two of the 9's as 99?

like root(9)!+99/9 or 99/9+9 or 99-9-9?

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wieczorek
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... :blinks: sometimes it just doesn't penetrate the upper epidermis until someone says it. thanks [Big Grin]
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5710
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Are decimals allowed in the answer?
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wieczorek
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no -today I was working on it with pi and got about .007 from being at 87, but I learned that no decimals were allowed.
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Happy Camper
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Got 3 in the 50s for you. 9*(√9)!+9/9, 9*(√9)!*9/9, and 9*(√9)!-9/9
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wieczorek
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Thank you so much. That's great. [Smile]

It actually took me a minute before I realized why I kept coming up with the same answer... [Big Grin]

[ September 30, 2003, 04:22 PM: Message edited by: wieczorek ]

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Paul Goldner
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Hrm.
So I was wrong.
I did the list very differently I guess [Smile]
I used funkiness with exponents.

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5710
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9squared-9-9-9=54
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wieczorek
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No worries, Paul [Smile]

5710, thanks alot. [Big Grin]

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Happy Camper
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Also managed to get a 57. 9*(√9)!+9/√9
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5710
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I was too late but no problem. I wish I got fun assignments like this.
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wieczorek
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Paul, I got 81 when I did that...I think I'm putting the parentheses in the wrong place... [Wink] Thanks so much.

5710 - I actually am finding myself enjoying this project, that's a foreign feeling... [Smile]

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wieczorek
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Nevermind Paul. I figured it out. [Smile]
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BannaOj
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wiezorek, you can get 7 pieces of cake right?

Have you been able to get 2 with your four 9s yet?

AJ

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Paul Goldner
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Yu can get 8 peices of cake.

Slice in half
stack on top, slice in half
take four peices and stack them. slice in half.

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wieczorek
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One of my friends came up with 8 -
1). cut the cake in half so you have to half circles
2). cut the halves in half so you have fourths
3). cut all of the four pieces you have in half (from the side so your knife is parallel with the table). I'm interested to see how you got 7, though.

Yes, I have 2. (9+9+9)/9. But I'm sure there are other ways. [Smile] Thanks

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Nato
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How many pieces of cake are you supposed to be able to get?

I think I can get ten, but probably a few more if I think about it longer. Or do you mean straight vertical cuts?

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wieczorek
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Paul beat me to it... [Wink]
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wieczorek
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Not necessarily vertical. Any straight cut you can come up with (but only 3 straight cuts are allowed total), Nato.

Well, only vertical and horizontal. Not diagonal.

[ September 30, 2003, 04:37 PM: Message edited by: wieczorek ]

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5710
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(9+9+9)/9 is three isnt it? 2 would be (9/9) + (9/9)
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BannaOj
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ah 2=99/9-9 sorry I started with the small numbers just to see what I could get before I knew you needed the 50s

AJ

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wieczorek
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sorry, 5710. I wrote the wrong number. For 2 I have : 9/9 + 9/9 and (99/9)-9. For 3 I have (9+9+9)/9 [Smile]

Don't worry BannaOj, I appreciate your help. It can't hurt to have more than 1 answer. [Smile]

[ September 30, 2003, 04:41 PM: Message edited by: wieczorek ]

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Christy
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quote:
Yes, I have 2. (9+9+9)/9. But I'm sure there are other ways. Thanks
Um? Math isn't quite my forte, but isn't that 3?

Edit:
*laugh* you guys are fast! I'm glad I wasn't going nuts.

[ September 30, 2003, 04:46 PM: Message edited by: Christy ]

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wieczorek
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[Roll Eyes] [Razz] [Big Grin]
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BannaOj
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I wasn't thinking about cylinder aspect or stacking, I was just doing 2-dimensional with the circle. You draw the three lines so that there is a triangle shaped piece in the center of the circle and there are three near triangles on the outside as well as three really odd shaped pieces. But it makes a total of 7.

AJ

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wieczorek
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I hadn't thought of that. My teacher would like to hear that one. [Smile]
EDIT- I've never seen a teacer before

[ September 30, 2003, 04:50 PM: Message edited by: wieczorek ]

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Papa Moose
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Are logarithms allowed?
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wieczorek
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I can't be sure...I'd have to ask to be positive, but there's no harm in trying [Wink]
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T. Analog Kid
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I don't think there is a possible way to get 10 pieces from three cuts unless you can fold the cake. A cut divides things into two pieces, so the very most you could get from three cuts would be 2^3 or 8.
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