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Author Topic: Stupid Math Questions (Game)
Geekazoid99
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The point of the game is to ask math questions that are totally worthless. First one to answer with the correct answer brings the next. (PLease giive questions with real knowable answers please)

First questions

What Percentage of Googolplex is 10?

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Irregardless
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(1 x 10 ^ -999999999999999999999999999999999 ...
9999999999999999999999999999999999 ...
999999999999999999999999999999998) %

?

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Geekazoid99
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YEs your right but please next time put as a fraction

Your turn aska stupid math question

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Reticulum
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What is complete Pi?
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Irregardless
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Well, it's my turn... and that's unanswerable... so let me think of one...
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mr_porteiro_head
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That's not unanswerable.

The answer is "Pi".

Another answer is "circumference/diameter".

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Irregardless
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Name any whole number (aside from 1) which is equal to the sum of the cubes of its digits.

I.e., XYZ = X^3 + Y^3 + Z^3 (where X, Y & Z are digits, not multiplied terms)

There are only 4 possible answers.

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mr_porteiro_head
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Zero.
Negative 1.

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Reticulum
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quote:
Originally posted by mr_porteiro_head:
That's not unanswerable.

The answer is "Pi".

Another answer is "circumference/diameter".

Hence the title "Stupid Math Questions". [Taunt]
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Irregardless
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Hmmm, I meant to specify positive integers (I was thinking that was what 'whole numbers' were). In any case, the 4 answers I referred to are all greater than 1.
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Irregardless
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Maybe I should have said 'cardinal numbers.'
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mr_porteiro_head
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You can't change the rules after I've already won.
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kaioshin00
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code:
 log(10^(ln(e^(log(10^(ln e^42)))))) 


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HollowEarth
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How many consecutive trailing zeros are there in Factorial(3^12)?

(For instance, 81! = 5 797 126 020 747 367 985 879 734 231 578 109 105 412 357 244 731 625 958 745 865 049 716 390 179 693 89
2 056 256 184 534 249 745 940 480 000 000 000 000 000 000 and has 19 consecutive trailing zeros.)

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Orincoro
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What is the lowers prime number with more than 3 digits which contains only prime numbers as integers. For example 13 contains all prime numbers, but 43 does not.
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Carrie
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Um, purple?
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Orincoro
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HA! Blue
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prolixshore
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How much wood would a woodchuck chuck if a woodchuck could chuck wood?

--ApostleRadio

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Irregardless
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quote:
Originally posted by mr_porteiro_head:
You can't change the rules after I've already won.

Fine, go ahead (although negative one was a wrong answer).
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Geekazoid99
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Acually -1 is a right answer

-1*-1=1
1*-1=-1

HE's right about that one Irregardless

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Irregardless
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Uh, no. (-1)^3 is -1, but I said the number is equal to the sum of the cubes of its digits. The digit in -1 is 1. 1^3 = +1.
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Irregardless
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BTW, how would you have expressed the answer to the Googolplex number as a fraction?
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mr_porteiro_head
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Irr is correct. -1 doesn't fit the rules he stated.

Zero does, though. [Evil]

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Geekazoid99
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Damn mistakes

What is .99999999999... squared

There's two answers

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mr_porteiro_head
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Since 0.9999999999999... is the same thing as 1.0, the answer is 1.0.
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Geekazoid99
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Thats one answer the other is if you take .99999999... to mean .999999... and is not 1
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mr_porteiro_head
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I have no idea what you just said.
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Geekazoid99
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I mean if you could write on a calculator .9999999999999999... and squared it what would the result be

If thats too hard here's an easy one

WHats the largest number you can make with 2 digits?

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kaioshin00
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Aw no one answered mine.

What is log(10^(ln(e^(log(10^(ln e^42))))))

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fugu13
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Geekazoid: I don't know about you, but I can keep adding factorial signs on the end of 99 until the cows come home.

Kaioshin: 42, of course

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Geekazoid99
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Oh i could do it alot easier like this

9↑↑↑↑↑↑↑↑↑9 IS probabbly already bigger than your writing with factorials

or even more of those bigger numbers

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HollowEarth
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Come on guy's, how many zeros? I assure you there is a simple way to get the right number. Look factorial(3^19) has 290565359 zeros.
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fugu13
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Geekazoid: you can't layer exponents like that, they're binary operators. Factorial, however, is a unary operator.
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mr_porteiro_head
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quote:
I mean if you could write on a calculator .9999999999999999... and squared it what would the result be
I say again that there is absolultely no difference between 0.99999999999.... (assuming the nines go on forever) and 1.0.
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Oviratptor
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quote:
What is .99999999999... squared
The two answers would be:

.99999999999... and 1

quote:
How many consecutive trailing zeros are there in Factorial(3^12)?

106288 zeroes.
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Reticulum
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Say, you wouldn't be the same Oviraptor who finds their way onto all of the Jp boards/ reg boards across the internet are you?
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Oviratptor
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quote:
Originally posted by Reticulum:
Say, you wouldn't be the same Oviraptor who finds their way onto all of the Jp boards/ reg boards across the internet are you?

Nope. I am only a member of one other forum. Only in that forum, I don't have a typo in my user name. [Wink]

Am I supposed to give a new math problem now?

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Reticulum
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Huh. Well, yes, you are. got any good ones?
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Oviratptor
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X^3 + Y^3 + Z^3 = 3

One soltution is (1,1,1)

Find 3 more using only integers.

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Irregardless
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(-5, 4, 4)
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human_2.0
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Exactly how big of ints?

This:

#!/usr/bin/perl

$start = -100;
$end = 100;

for ( $x = $start; $x lt $end ; $x++ ) {
for ( $y = $start; $y lt $end ; $y++ ) {
for ( $z = $start; $z lt $end ; $z++ ) {
if ( $x*$x*$x + $y*$y*$y + $z*$z*$z == 3 ) {
print "x $x y $y z $z\n";
}
}
}
}

(the forum wouldn't let me include less then, so I have lt instead)

says the answers are:

(-5, 4, 4)
(1, 1, 1)
(4, -5, 4)
(4, 4, -5)

I have a grid running right now... Should I submit this with a humongoidly large range? hahahahaha

I was running -1000 to 1000 but my laptop got so hot it shut itself off.

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Jonathan Howard
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How come if I hand out no oranges to no kids, each of them has an orange I handed to them?!
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mr_porteiro_head
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For the same reason each one of them has no oranges, and each one has exactly PI oranges.
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Althai
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quote:
Name any whole number (aside from 1) which is equal to the sum of the cubes of its digits.

I.e., XYZ = X^3 + Y^3 + Z^3 (where X, Y & Z are digits, not multiplied terms)

There are only 4 possible answers.

153
370
371
407

quote:
What is the lowers prime number with more than 3 digits which contains only prime numbers as integers. For example 13 contains all prime numbers, but 43 does not
I assume you mean all prime digits? So only contains the digits 2,3,5,7? Then it would be:
2237
If you also allow 1, which is not actually prime, but appears in your example, the answer would be:
1117

New question:
Can you find five points on a sphere so that no four of them lie in a single closed hemisphere? ("Closed" means "including the boundary circle") Why or why not?

David

[ April 13, 2006, 10:10 PM: Message edited by: Althai ]

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