posted
Yeah, inky quills is my second favorite. But since I first came across the Poe one in The Annotated Alice many moons ago, that's the one I tend to remember.
Posts: 32919 | Registered: Mar 2003
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posted
Sorry, Hobbes, I realized I hadn't seen your response earlier.
You can't change the pointers themselves, and I'm not asking for a concrete solution, I'm asking for an abstract solution. This is an exercise in puzzle based thinking, not good enough thinking.
Plus, you're wrong. Computer storage nowadays can easily hold a list long enough to be more than the capacity of a pointer. I fail to see why it would crash, as well.
Edit: I'm guessing your talking about memory addressing capabilities. First, one can have a linked list on the hard disk and have parts of it brought into memory as needed. I didn't specify the implementation. Second, even were it all in memory, that's actually not a complete limitation. Its theoretically possible for each member of the list to be restricted to under a machine word, using an extremely compact notation.
We are very little creatures, all of us have different features. One of us in glass is set; one of us you'll find in jet. Another you may see in tin, and a fourth is boxed within. If the fifthyou should pursue, it can never fly from you. What are we?
posted
The beginning of eternity The end of time and space The beginning of every end, And the end of every place.
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I never was, am always to be, No one ever saw me, nor ever will, And yet I am the confidence of all To live and breathe on this terrestrial ball. What am I?
Posts: 32919 | Registered: Mar 2003
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posted
I've done the cored ball problem, answers relating to counterintuitive results of dimensionality changes never surprise me any more.
Actually, that's a decent riddle, though many of the people able to answer it will probably have done it before. Of course, many of them may have forgotten .
You have a perfect wooden sphere. You drill a cylinder through the middle such that the remaining ring of wood is exactly 2" high (when measured along the cylindrical hole). What is the volume of the remaining wood?
Note: I've forgotten the answer, so I'll have to work it out for myself. I'll have it in a sec, but if you post an answer quickly post your work as well so I can just check that.
Posts: 15770 | Registered: Dec 2001
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posted
OK, I don't want to do the math, but it's clear the size of the sphere doesn't matter, which means the diameter of the hole doesn't matter. So assume a zero-radius hole, which means a 2" sphere. So it's equal to the volume of a 2" sphere, right?
I can't prove this mathematically, because I don't remember how to do the partial volume of a sphere intercepted by a plane.
Either that or you left out some critical information. If you didn't, I think I have to be right.
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